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Life Processes – PYQ Interactive Quiz

  Life Processes – PYQ Interactive Quiz Chapter: Life Processes | Class 10 Biology (NCERT) Score: 0 / 25 1. Which of the following are energy foods? (a) Carbohydrates and fats (b) Proteins and minerals (c) Vitamins (d) Water Check Answer 2. Nutrition from a living host without killing it: Saprotrophic Parasitic Holozoic Autotrophic Check Answer 3. Mode of nutrition in fungi: Parasitic Holozoic Autotrophic Saprotrophic Check Answer 4. Roots absorb water by: Diffusion Transpiration Osmosis Mass flow Check Answer 5. Site of photosynthesis: Chloroplast Mitochondria Cytoplasm Protoplasm Check Answer 6. Digestion in Amoeba occurs in: Food vacuole Mitochondria Pseudopodia Chloroplast Check Answer 7. Absence of salivary amylase affects: Starch digestion Protein digestion Vitamin absorption Fat digestion Check Answer 8. Digested food is absorbed in: Stomach Small intestine Large...

Life Processes- Revision capsule CBSE class 10th

  Life Processes – Smart & Complete Quick Revision (Class 10) This chapter explains the basic activities that keep organisms alive — nutrition, respiration, transport, and excretion — with strong emphasis on comparison, reasoning, and flow-based questions. 1. What Are Life Processes? Life processes are the essential functions performed by living organisms to maintain life. These include obtaining food, releasing energy, transporting materials, and removing wastes. Exam Insight: Viruses show life processes only inside a host — a favourite reasoning MCQ. 2. Nutrition Modes of Nutrition Autotrophic: Plants prepare food using sunlight Heterotrophic: Animals depend on others Photosynthesis (High Weightage) Occurs in chloroplasts using chlorophyll. $$ 6CO_2 + 6H_2O \xrightarrow{Sunlight, Chlorophyll} C_6H_{12}O_6 + 6O_2 $$ Stomata regulate gas exchange Light reaction → ATP, NADPH Dark reaction → glucose formation Trap: Oxygen released comes ...

Carbon and Its Compounds - Revision Capsule CBSE class 10

  Carbon and Its Compounds – Smart & Complete Quick Revision (Class 10) Carbon is the backbone of life and organic chemistry. Its ability to form strong covalent bonds, long chains, branches, and rings makes it unique among all elements. This chapter explains why carbon forms millions of compounds and how these compounds behave in daily life and exams. 1. Why Carbon Forms So Many Compounds Carbon shows catenation (self-linking) and tetravalency . Each carbon atom forms four covalent bonds, leading to stable chains and rings. Example bond formation: $$ \text{Carbon valency} = 4 \Rightarrow \text{forms single, double, or triple bonds} $$ Exam Tip: Silicon also shows catenation, but carbon does it best due to smaller size and stronger C–C bonds. 2. Covalent Compounds – Key Properties Carbon compounds are mostly covalent because carbon does not easily lose or gain electrons. Low melting and boiling points Poor conductors of electricity Generall...

Carbon & Its Compounds 25 PYQ-Based MCQ Practice Quiz

  Class 10 Science – Carbon & Its Compounds 25 PYQ-Based MCQ Practice Quiz High-yield CBSE PYQ-pattern MCQs covering hydrocarbons, ethanol, ethanoic acid, soaps, detergents & reactions. 1. The valency of carbon is: Difficulty: Easy 2 3 4 5 Show Answer Answer: 4 Carbon forms four covalent bonds. 2. Which property enables carbon to form long chains? Difficulty: Easy Isomerism Catenation Saturation Oxidation Show Answer Answer: Catenation 3. Which of the following is a saturated hydrocarbon? Difficulty: Easy Ethene Ethyne Methane Benzene Show Answer Answer: Methane 4. The general formula of alkanes is: Difficulty: Easy CₙH₂ₙ CₙH₂ₙ₊₂ CₙH₂ₙ₋₂ CₙHₙ Show Answer Answer: CₙH₂ₙ₊₂ 5. Which reaction converts vegetable oil into ghee? Difficulty: Moderate Oxidation Esterification Hydrogenation Fermentation Show Answer Answer: Hydrogenation 6. Ethanol reacts with sodium to produce: Difficu...

Metals & Non-Metals 25 PYQ-Based MCQ

  Class 10 Science – Metals & Non-Metals 25 PYQ-Based MCQ Practice Quiz Practice important CBSE Class 10 PYQ-pattern MCQs with difficulty levels and explanations. 1. Which metal can be cut with a knife? Difficulty: Easy Iron Aluminium Sodium Copper Show Answer Answer: Sodium Very soft and reactive. 2. Which non-metal conducts electricity? Difficulty: Easy Sulphur Graphite Oxygen Phosphorus Show Answer Answer: Graphite Free electrons allow conduction. 3. Which gas is released when zinc reacts with dilute HCl? Difficulty: Easy Oxygen Hydrogen Carbon dioxide Nitrogen Show Answer Answer: Hydrogen Metal + acid → salt + H₂ 4. Which metal is stored under kerosene? Difficulty: Easy Magnesium Iron Sodium Copper Show Answer Answer: Sodium Highly reactive with air and water. 5. Which metal does not react with dilute acids? Difficulty: Moderate Iron Zinc Copper Aluminium Show Answer Answer: Coppe...

Metals and Non-Metals – Quick Revision Notes (Class 10)

  Metals and Non-Metals – Quick Revision Notes (Class 10) A compact yet exam-oriented revision guide covering properties, reactions, metallurgy, corrosion, and everyday applications of metals and non-metals — perfectly curated for CBSE Class 10 . 1. Physical Properties Metals Generally hard, shiny, malleable, ductile Good conductors of heat & electricity High melting & boiling points (except Na, K) Non-Metals Generally dull, brittle (exception: diamond) Poor conductors (exception: graphite) Low melting & boiling points CBSE Trap: Mercury is a metal but liquid at room temperature. 2. Chemical Properties of Metals (a) Reaction with Oxygen Metal + Oxygen → Metal oxide $2Mg + O_2 \rightarrow 2MgO$ Tip: Metal oxides are generally basic . (b) Reaction with Water K, Na → Violent reaction Ca → Less violent Mg → Hot water Fe → Steam $2Na + 2H_2O \rightarrow 2NaOH + H_2 \uparrow$ (c) Reaction with ...

Class 10 Mathematics – PYQ Objective Quiz

Class 10 Mathematics – PYQ Objective Quiz Previous Year Questions | MCQs with Answer Reveal 1. Which of the following equations has the sum of its roots as 3? (A) x² + 3x − 5 = 0 (B) −x² + 3x + 3 = 0 (C) √2x² − (3x)/√2 − 1 = 0 (D) 3x² − 3x − 3 = 0 Check Answer Answer: (B) Reason: Sum of roots = −b/a = −3/−1 = 3 2. The sum of first five multiples of 3 is (A) 45 (B) 65 (C) 75 (D) 90 Check Answer Answer: (A) 3 + 6 + 9 + 12 + 15 = 45 3. If radii of the two concentric circles are 15 cm and 17 cm, then the length of each chord of one circle which is tangent to the other is (A) 8 cm (B) 16 cm (C) 30 cm (D) 17 cm Check Answer Answer: (B) Half chord = √(17² − 15²) = 8 → Full = 16 cm 4. In Fig. 1, PQ and PR are tangents to the circle with centre O such that ∠QPR = 50°, then angle OQR is equal to (A) 25° (B) 30° (C) 40° (D) 50° Check Answer Answer: (A) Angle between tangents = 180° − ∠QOR = 180° − 130° = 50° ∠OQR ...

Ionic Equilibrium – Complete Formula & Concept Sheet

  Ionic Equilibrium – Complete Formula & Concept Sheet (JEE Main + Advanced) Ionic equilibrium deals with reversible ionisation in aqueous solutions . This chapter merges equilibrium, logarithms, and electrostatics of ions . 1. Electrolytes Strong electrolytes: Complete ionisation (HCl, NaOH) Weak electrolytes: Partial ionisation (CH₃COOH, NH₄OH) Trap: Strong electrolyte ≠ concentrated, weak electrolyte ≠ dilute 2. Ionisation of Water H₂O ⇌ H⁺ + OH⁻ K w = [H⁺][OH⁻] = 1.0 × 10 −14 (at 25°C) Pure water: [H⁺] = [OH⁻] = 10 −7 M Neutral ≠ pH 7 at all temperatures 3. pH, pOH and Scale pH = −log[H⁺] pOH = −log[OH⁻] pH + pOH = 14 (at 25°C) Classic Trap: Log values must be approximated correctly (10⁻⁵.⁶ ≠ 4×10⁻⁶) 4. Weak Acids (Ka) For a weak acid HA: HA ⇌ H⁺ + A⁻ K a = [H⁺][A⁻] / [HA] If initial concentration = C and degree of ionisation = α: K a = Cα² / (1 − α) ≈ Cα² (if α ≪ 1) [H⁺] = √(K a · C) 5. Weak Bases...

Chemical Equilibrium – Complete Formula & Concept Sheet

  Chemical Equilibrium – Complete Formula & Concept Sheet (JEE Main + Advanced) Chemical equilibrium deals with reversible reactions where forward and backward reaction rates become equal. Equilibrium is dynamic , not static. 1. Law of Mass Action For a general reaction: aA + bB ⇌ cC + dD The equilibrium constant: K c = [C] c [D] d / [A] a [B] b Only concentration of gases and solutes appear Pure solids and liquids are omitted 2. Equilibrium Constant K c and K p For gaseous reactions: K p = K c (RT) Δn where Δn = (moles of gaseous products − moles of gaseous reactants) Trap: Δn counts only gases, not solids or liquids. 3. Reaction Quotient (Q) Same expression as K c , but using initial concentrations . Q < K → Reaction proceeds forward Q > K → Reaction proceeds backward Q = K → System at equilibrium 4. Characteristics of Chemical Equilibrium Equilibrium can be achieved from either side Equilibrium consta...

Atomic Structure – Complete Conceptual & Numerical Revision

  Atomic Structure – Complete Conceptual & Numerical Revision Atomic Structure explains why atoms behave the way they do. JEE doesn’t test history — it tests quantization, wave–particle duality, hydrogen spectrum logic, and hidden unit traps . 1. Fundamental Picture of Atom Atom consists of nucleus (protons + neutrons) surrounded by electrons. Classical physics fails → quantum concepts required. Key Idea: Electron does NOT move in a classical orbit — it exists as a probability wave 2. Photoelectric Effect (Concept + Formula) When light of frequency ≥ threshold frequency strikes a metal, electrons are ejected. $E = h\nu$ $h\nu = h\nu_0 + KE_{max}$ $KE_{max} = \frac{1}{2}mv^2 = h(\nu - \nu_0)$ JEE Trap: Intensity affects number of electrons, NOT their kinetic energy 3. Dual Nature of Matter (de Broglie) Every moving particle behaves like a wave. $\lambda = \dfrac{h}{p} = \dfrac{h}{mv}$ $\lambda = \dfrac{h}{\sqrt{2mKE}}$ Trap: El...

Mole Concept - Revision capsule JEE Mains

  Mole Concept – Complete Quantitative Chemistry Revision The Mole Concept is the backbone of Physical Chemistry. Almost every numerical problem in chemistry starts or ends here. JEE tests this chapter through unit conversion, limiting reagent logic, stoichiometry, and concentration traps . 1. Fundamental Definitions Mole: Amount of substance containing $6.022 \times 10^{23}$ entities Avogadro Number: $N_A = 6.022 \times 10^{23} \, mol^{-1}$ Molar Mass: Mass of 1 mole of a substance (in g/mol) Golden Relation: $\text{Moles} = \dfrac{\text{Given quantity}}{\text{Molar mass}}$ 2. Mole – Particle – Mass Relations $\text{Number of particles} = n \times N_A$ $n = \dfrac{w}{M}$ JEE Trap: Atoms vs molecules vs ions — always check entity asked 3. Mole Concept in Gases Molar Volume (STP): $1 \text{ mole gas} = 22.4 \, L \; (STP)$ $n = \dfrac{V}{22.4} \quad (STP)$ Using Ideal Gas Equation: $PV = nRT$ Trap: STP vs RTP confusion ...

Hydrocarbons – Complete NCERT Revision

  Hydrocarbons – Complete NCERT Revision (Reactions + Mechanisms) Hydrocarbons are organic compounds containing only carbon and hydrogen. This chapter is heavily tested in JEE Main via reactions and in Advanced via mechanisms & exceptions. 1. Alkanes (Paraffins) General formula: $C_nH_{2n+2}$ Hybridisation: $sp^3$ (tetrahedral, $109.5^\circ$) Preparation of Alkanes Wurtz Reaction: $2R–X + 2Na \rightarrow R–R + 2NaX$ Limitation: Mixture with different alkyl halides

How to Revise Effectively for JEE Main 2026

  How to Revise Effectively for JEE Main 2026 (Science-Backed Strategy) Revising for JEE Main is not about reading the same notes again and again. If that worked, every sincere student would already be confident. The real problem is this: most students revise passively, but JEE tests active recall, speed, and accuracy under pressure. This post explains a scientifically correct revision system that actually improves scores, not just comfort. 1. What Revision Really Means for JEE Main Revision is not: Re-reading NCERT again and again Highlighting formulas without application Watching the same lectures repeatedly Revision is: Recalling concepts without looking Identifying conceptual gaps Training your brain to think under time pressure JEE does not ask, “Have you seen this?” It asks, “Can you apply this in 90 seconds?” 2. The 3-La...

Chemical Bonding – JEE mains PYQ series

  Score: 0 Attempted: 0 Chemical Bonding – Interactive PYQ Quiz Topic: Molecular Geometry & VSEPR | JEE Main PYQs Q1. [16 March 2021 | Shift-1] Assertion: H–O–H bond angle in water is 104.5°. Reason: Lone pair–lone pair repulsion is maximum. A is false but R is true Both true but R not explanation A true, R false Both true and R correct explanation Check Answer Lone pair–lone pair repulsion compresses bond angle below 109.5°. Q2. [JEE Main 2024] Correct increasing order of bond angles: BF₃ < PF₃ < ClF₃ PF₃ < BF₃ < ClF₃ ClF₃ < PF₃ < BF₃ BF₃ = PF₃ < ClF₃ Check Answer ClF₃ (T-shape) < PF₃ (pyramidal) < BF₃ (120°). Q3. [11 April 2023 | Shift-1] Match geometries correctly: A-III, B-II, C-I, D-IV A-III, B-I, C-II, D-IV A-III, B-IV, C-I, D-II A-III, B-IV, C-II, D-I Check Answer H₂O⁺ → pyramidal, acetylide → linear, NH₃ → pyramidal, ClO₂⁻ → bent. Q4. [27 Jan 2022 | Shi...

Circular Motion – Complete Formula & Concept Revision

    Circular Motion – Complete Formula & Concept Revision Circular motion refers to motion of a particle along a circular path. Although speed may remain constant, velocity always changes due to continuous change in direction. 1. Angular Quantities Angular displacement: $\theta$ (radians) Angular velocity: $\omega = \dfrac{d\theta}{dt}$ Angular acceleration: $\alpha = \dfrac{d\omega}{dt}$ Relation with linear quantities: $v = r\omega$ $a_t = r\alpha$ $a_c = r\omega^2 = \dfrac{v^2}{r}$ 2. Time Period & Frequency Time period: $T = \dfrac{2\pi}{\omega}$ Frequency: $f = \dfrac{1}{T}$ $\omega = 2\pi f$ 3. Centripetal Acceleration $a_c = \dfrac{v^2}{r} = r\omega^2$ Always directed toward centre Changes direction of velocity, not magnitude Trap: Zero centripetal acceleration means no circular motion. 4. Non-Uniform Circular Motion Acceleration has two components: Centripetal: $a_c = \dfrac{v^2}{r}$ Tangential: $a_t = \dfr...

Work, Energy and Power – Complete JEE Revision

    Work, Energy and Power – Complete JEE Revision This chapter connects force and motion through energy. JEE loves testing signs, reference frames, variable forces, and conservation traps . 1. Work (a) Work by Constant Force $W = \vec{F}\cdot\vec{s} = Fs\cos\theta$ Work depends on the component of force along displacement . $\theta=0^\circ$ → Maximum work $\theta=90^\circ$ → Zero work (centripetal force) $\theta=180^\circ$ → Negative work (b) Variable Force $W = \int \vec{F}\cdot d\vec{r}$ Work equals area under F–x graph . 2. Special Forces & Work Gravity: Conservative → path independent Friction: Non-conservative → path dependent Normal force: Usually zero work Centripetal force: Always zero work 3. Kinetic Energy (KE) $K = \frac{1}{2}mv^2$ Work–Energy Theorem Net work done = Change in kinetic energy $W_{\text{net}} = \Delta K$ Applies even when forces are complicated. 4. Potential Energy (PE) (a) Gr...