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Alternating current PYQ series

 Q. An alternating voltage v(t) = 220 sin 100tr volt is applied to a purely resistive load of 50 2. The time taken for the current to rise from half of the peak value to the peak value is

                                                           ( JEE mains 2029)

A. 2.2 ms


B. 5 ms


C. 3.3 ms


4.7.2 ms

Ans:- (C)


Phase Analysis Answer

cos θ = (V0 / 2) / V0 = 1/2

∴ θ = π / 3

Time taken for phase change by π / 3 is

t1 = θ / ω = (π / 3) / 100π = 1/300 = 3.33 ms

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