Q. The reaction of zinc with excess of aqueous alkali, evolves hydrogen gas and gives:
( JEE mains 2022)1. Zn(OH)2
2. ZnO
3. [Zn(OH)4]²-
4. [ZnO2]²–
Ans :- [D]
Zinc dissolves in excess of aqueous alkali
Zn + 2OH + 2H2O→ [Zn(OH)4]² + H₂ ↑ Tetrahydroxozincate(II) ion
However, this reaction in NCERT is given as Zn+2NaOH → Na,ZnO, + H, ↑
ZnO² is anhydrous form of [Zn(OH)4] 2- So in aqueous medium best answer of this question is [Zn(OH)4]²-
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